r^2+9r=62

Solution for r^2+9r=62 equation:

r^2+9r=62

We move all terms to the left:

r^2+9r-(62)=0

a = 1; b = 9; c = -62;
Δ = b2-4ac
Δ = 92-4·1·(-62)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{329}}{2*1}=\frac{-9-\sqrt{329}}{2}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{329}}{2*1}=\frac{-9+\sqrt{329}}{2}
$